How do I pass parameters in C?

I'm a beginning C programmer, trying to write a simple little program. The goal is to find the cube of a number (i.e. 2 * 2 * 2=8), by using a self-made function and then passing the argument from the main function to the self-made function then having that number go back to the main function and print the result. Here's what I have:





#include %26lt;stdio.h%26gt;


int test(int first);


int main(void)


{


int number, cube;


printf("Please enter a number: ");


number = scanf("%d", %26amp;number);


cube = test(number);


printf("The cube is %d\n", cube);


return 0;


}





int test(int first)


{


int a, b;


b = first;


a = b * b * b;


return a;


}





I can't figure out what's wrong. Any help would be greatly appreciated!

How do I pass parameters in C?
Here is yours problem:


%26gt;%26gt; number = scanf("%d", %26amp;number);





scanf first scans for the desired formatted string and stores the value in number, but returns the number of extract tokens, 1 in this case, which gets stores also in numbers. After that line, numbers will always be one.





correcct it to:


scanf("%d", %26amp;number);





and it should work also.





Also, you can simply implement test as


int first (int n) {


return n * n * n;


}
Reply:in your program,error part is number=scanf("%d",%26amp;number);


if you use this statement, the output is 1.
Reply:when you compile what does it do, does it give you a correct number or does it output wrong, im not good with C but i do know C++ and that program is pretty much the same as my C++ i know, my yim is in my profile, if you want to yim me i can help you through it





btw, i wouldnt call the main function as void just leave it blank ()