C Programmers, help me please...?

how can I count a certain letter or digit in a word?





let's say





MISSISSIPPI





1=M


4=I


4=S


2=P





it would me more appreciated if your answer would be string, array, etc.

C Programmers, help me please...?
char *mystring = "MISSISSIPPI";


int length = strlen(mystring);





int countletters(char str[])


{


int count = 0, k = 0;


while (str[k] != '\0')


{


if (str[k] == 'YOUR LETTER')


count++;


k++;


}


return count;


}





hope this will solve your issues





Cheers:)
Reply:hello friends! i am prabhakar gunturi. iam sure that below solution will work. after that you please send this type of questions to my mail. waiting for your mail.








#include%26lt;stdio.h%26gt;


#include%26lt;conio.h%26gt;


#include%26lt;string.h%26gt;


static int flag[100];


void main()


{


static int count,l,i,j;


char sentence[100];


clrscr();


printf("enter any string");


gets(sentence);


l=strlen(sentence);


for(i=0;i%26lt;l;i++)


{


count=1;


for(j=0;j%26lt;l;j++)


{


if(flag[i]!=1)


{


if(toupper(sentence[i])==toupper(sentenc...


{


count++;


flag[j]=1;


}


}


}


if(flag[i]!=1)


printf("The character %c presents %d times in the given string",sentence[i],count);


}
Reply:If you're looking for a specific character, do:





int CountCharacters(char *str, char find)


{


int count;





for (count=0; *str; str++ )


{


if ( *str == find )


count += 1;


}





return count;


}





Building on that (although definitely not especially efficient since it requires scanning the string for each letter), if you wanted output:





void CountCharacters(char *str)


{


char *find;


char *findPointer;


find = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";





for ( findPointer = find; *findPointer; findPointer++ )


{


int count;





count = CountCharacters(str, *findPointer);


if ( count %26gt; 0 )


{


cout %26gt;%26gt; *findPointer %26gt;%26gt; "=" %26gt;%26gt; count %26gt;%26gt; "\r\n";


}


}


}
Reply:qsort(string,sizeof(char),strlen(string)...


char*ptr = string1;


char chars[strlen(string)] = {0,0};


int count[strlen(string)] = {1,1....};


i=0;


while(*ptr)


{


if(*prt == *(ptr+1))


{chars[i] = *ptr;count[i]++;}


else


{chars[i] = *ptr;i++;}


}

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